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New league rankings method

 
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statsgenie
Founding Father
Founding Father


Joined: 03 Mar 2005
Posts: 21
Location: Montreal / Canada

PostPosted: Thu Mar 03, 2005 1:52 pm    Post subject: New league rankings method Reply with quote

Hi all, here is the rankings method we use (We've just started out with our league, but so far, the results seem OK).

For PAIR number of buyins
- No 0 point player
- Max Points= Buyins * 5 / 2

for ODD number of buyins:
- Will have a 0 point player
- Max Points= ((Buyins * 5) – 5) / 2

- We start from Max Points Down the rankings by increments of 5
- We add + 3 to the winner and +1 to runner up

Exemple:
12 player Tourney: Max Points= 12 * 5 / 2 = 30
1= 30 + 3 = 33
2= 25 + 1 = 26
3= 20
4= 15
5= 10
6= 5
7=-5
8= -10
9= -15
10= -20
11= -25
12= -30

11 player Tourney: Max Points= ((11 * 5) -5) / 2 = 25
1= 25 + 3 = 28
2= 20 + 1 = 21
3= 15
4= 10
5= 5
6= 0
7=-5
8= -10
9= -15
10= -20
11= -25

The total rankings is the sum of all rankings.
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jumperjeff
"Miracle Flush"


Joined: 14 Feb 2005
Posts: 118
Location: Edmonton, AB

PostPosted: Thu Mar 03, 2005 4:15 pm    Post subject: Reply with quote

I'm curious why you did the -5 in the equation for the Odd number of buy-ins.
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statsgenie
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Joined: 03 Mar 2005
Posts: 21
Location: Montreal / Canada

PostPosted: Thu Mar 03, 2005 5:46 pm    Post subject: Reply with quote

Well.... initially (before we added 1st and 2nd place bonuses) the idea was, for any given tournament, to assign a total of 0 points. This would ensure that no one has an advantage if they play in more tournaments. With the added bonuses, this is slightly untrue, but still semi-true Smile

I consider it better than an average system, since with an average system, a good player that plays in smaller tournaments will never be able to compete with an average player that only plays in big tournaments...

Another reason, is not to have decimal points (but this is merely a question of taste)


So if we take this same exemple:
11 player Tourney: Max Points= ((11 * 5) -5) / 2 = 25
1= 25 + 3 = 28
2= 20 + 1 = 21
3= 15
4= 10
5= 5
6= 0
7=-5
8= -10
9= -15
10= -20
11= -25

Total points given= 4 (1st bonus 3 + 2nd bonus 1) normally would be 0


and if we remove the -5:
11 player Tourney: Max Points= ((11 * 5) ) / 2 = 27.5
1= 27.5 + 3 = 30.5
2= 22.5 + 1 = 23.5
3= 17.5
4= 12.5
5= 7.5
6= 2.5
7=-2.5
8= -7.5
9= -12.5
10= -17.5
11= -22.5

Total points given= 31.5 (3 for 1st, 1 for 2nd ) wich leaves an offset of 27.5 points for the tournament.....

Anyways, a lot of numbers to say not much... But hope it answers your question Smile
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drneau
Site Admin


Joined: 13 Feb 2005
Posts: 2385
Location: Woodbury, MN

PostPosted: Sun Jun 12, 2005 10:06 pm    Post subject: Reply with quote

You can now implement this in the tool.
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